(2x^2-22x)/6=63

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Solution for (2x^2-22x)/6=63 equation: 


x in (-oo:+oo)

(2*x^2-(22*x))/6 = 63 // - 63

(2*x^2-(22*x))/6-63 = 0

(2*x^2-22*x)/6-63 = 0

(2*x^2-22*x)/6+(-63*6)/6 = 0

2*x^2-22*x-63*6 = 0

2*x^2-22*x-378 = 0

2*x^2-22*x-378 = 0

2*(x^2-11*x-189) = 0

x^2-11*x-189 = 0

DELTA = (-11)^2-(-189*1*4)

DELTA = 877

DELTA > 0

x = (877^(1/2)+11)/(1*2) or x = (11-877^(1/2))/(1*2)

x = (877^(1/2)+11)/2 or x = (11-877^(1/2))/2

2*(x-((11-877^(1/2))/2))*(x-((877^(1/2)+11)/2)) = 0

(2*(x-((11-877^(1/2))/2))*(x-((877^(1/2)+11)/2)))/6 = 0

(2*(x-((11-877^(1/2))/2))*(x-((877^(1/2)+11)/2)))/6 = 0 // * 6

2*(x-((11-877^(1/2))/2))*(x-((877^(1/2)+11)/2)) = 0

( 2 )

2 = 0

x belongs to the empty set

( x-((11-877^(1/2))/2) )

x-((11-877^(1/2))/2) = 0 // + (11-877^(1/2))/2

x = (11-877^(1/2))/2

( x-((877^(1/2)+11)/2) )

x-((877^(1/2)+11)/2) = 0 // + (877^(1/2)+11)/2

x = (877^(1/2)+11)/2

x in { (11-877^(1/2))/2, (877^(1/2)+11)/2 }

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